nml::mat2 operator+(nml::mat2 lhs, const nml::mat2& rhs)

Return a mat2 that is the sum between two mat2.

The sum between two mat2 is calculated this way:

\(\begin{bmatrix} lhs.x.x & lhs.y.x \\ lhs.x.y & lhs.y.y \end{bmatrix} + \begin{bmatrix} rhs.x.x & rhs.y.x \\ rhs.x.y & rhs.y.y \end{bmatrix} = \begin{bmatrix} lhs.x.x + rhs.x.x & lhs.y.x + rhs.y.x \\ lhs.x.y + rhs.x.y & lhs.y.y + rhs.y.y \end{bmatrix}\)

Example

#include "include/mat2.h"
#include <iostream>

int main() {
        nml::mat2 a(1.0f, 2.0f, 4.0f, 8.0f);
        nml::mat2 b(2.0f, 4.0f, 6.0f, 8.0f);
        nml::mat2 c = a + b;
        std::cout << nml::to_string(c) << std::endl;

        return 0;
}

Result:

[[3.000000, 6.000000], [10.000000, 16.000000]]