bool operator!=(const nml::mat2& lhs, const nml::mat2& rhs)

Return true if the two mat2 are different, else, return false.

The inequality between two mat2 is calculated this way:

\(\small \begin{bmatrix} lhs.x.x & lhs.y.x \\ lhs.x.y & lhs.y.y \end{bmatrix} \neq \begin{bmatrix} rhs.x.x & rhs.y.x \\ rhs.x.y & rhs.y.y \end{bmatrix} =\)

\(\small (lhs.x.x \neq rhs.x.x) or (lhs.y.x \neq rhs.y.x) or\) \(\small (lhs.x.y \neq rhs.x.y) or (lhs.y.y \neq rhs.y.y)\)

Example

#include "include/mat2.h"
#include <iostream>

int main() {
        nml::mat2 a(1.0f, 2.0f, 3.0f, 4.0f);
        nml::mat2 b(3.0f, 2.0f, 5.0f, 1.0f);
        bool c = (a != b);
        std::cout << c << std::endl;

        return 0;
}

Result:

1